Aaron Rodgers’ reign at the top is over:
Full details for the #Seahawks and QB Russell Wilson: 4 new years, $140M. $65M to sign. Total guarantee: $107M. A no-trade clause. … Now, Wilson is under contract for 5 years and $157M. And staying in Seattle.💰💰💰
— Ian Rapoport (@RapSheet) April 16, 2019
NFL Network insider Ian Rapoport reports the Seahawks and Russell Wilson have agreed to a four-year extension that makes him the NFL’s highest-paid player. The deal includes $107 million in total guarantees, a signing bonus of $65 million, and is worth up to $140 million. It also includes a no-trade clause, which means Seattle’s franchise quarterback isn’t going anywhere any time soon. And why would the Seahawks want it any other way?
Wilson has made the Pro Bowl five times, including two of the last three years. And over the last four seasons, Wilson has averaged 3,918 yards, 31 touchdowns, and 9 interceptions. That comes out to an impressive 6.2 TD% and minuscule 1.8 Int%, which has helped cement his place among football’s best quarterbacks. Oh, and his Seahawks have won at a 66.9 percent clip since his rookie season in 2012 – a stretch in which Wilson hasn’t missed a game. It’s as impressive as a run as you’ll get from a quarterback.
As quarterback salaries continue to rise, we’ll continue to keep track of them because they will (hopefully) be applicable to Mitch Trubisky one day. Trubisky is just two years into his NFL career, but the Bears will have to come to a long-term decision regarding their quarterback’s future if he continues to make improvements to his game and the team keeps winning games. We’re not quite ready to start mapping out contract projections for Trubisky just yet, but recent history suggests it could be on our mind sooner than we expect.